a sample of iron (fe) with a mass of 200.0 g releases 9,840 cal when it freezes at its freezing point. what…

a sample of iron (fe) with a mass of 200.0 g releases 9,840 cal when it freezes at its freezing point. what is the molar heat of fusion for iron? use q = nδh. 2,747.7 cal/mol 2,771.8 cal/mol 2,811.7 cal/mol 3,280.0 cal/mol

a sample of iron (fe) with a mass of 200.0 g releases 9,840 cal when it freezes at its freezing point. what is the molar heat of fusion for iron? use q = nδh. 2,747.7 cal/mol 2,771.8 cal/mol 2,811.7 cal/mol 3,280.0 cal/mol

Answer

Answer:

2,771.8 cal/mol

Explanation:

Step1: Calcular la cantidad de moles de hierro

La masa atómica del hierro (Fe) es aproximadamente 55.85 g/mol. La cantidad de moles ($n$) se calcula como $n=\frac{m}{M}$, donde $m = 200.0$ g y $M=55.85$ g/mol. Entonces $n=\frac{200.0}{55.85}\approx3.581$ mol.

Step2: Calcular el calor molar de fusión

Se sabe que $q = n\Delta H$. Re - arreglando la fórmula para $\Delta H$, se obtiene $\Delta H=\frac{q}{n}$. Dado que $q = 9840$ cal y $n\approx3.581$ mol, entonces $\Delta H=\frac{9840}{3.581}\approx2771.8$ cal/mol.