a sample of propane (c₃h₈) has a mass of 0.47 g. the sample is burned in a bomb calorimeter that has a mass…

a sample of propane (c₃h₈) has a mass of 0.47 g. the sample is burned in a bomb calorimeter that has a mass of 1.350 kg and a specific heat of 5.82 j/(g·°c). how much energy is released by the reaction if the temperature of the calorimeter rises by 2.87°c? use q = mcₚδt.\n7.85 kj\n10.6 kj\n22.5 kj\n47.9 kj

a sample of propane (c₃h₈) has a mass of 0.47 g. the sample is burned in a bomb calorimeter that has a mass of 1.350 kg and a specific heat of 5.82 j/(g·°c). how much energy is released by the reaction if the temperature of the calorimeter rises by 2.87°c? use q = mcₚδt.\n7.85 kj\n10.6 kj\n22.5 kj\n47.9 kj

Answer

Explanation:

Step1: Convert mass of calorimeter to grams

$1.350\ kg = 1.350\times1000\ g= 1350\ g$

Step2: Apply the heat - transfer formula

$q = mC_p\Delta T$, where $m = 1350\ g$, $C_p=5.82\ J/(g\cdot^{\circ}C)$ and $\Delta T = 2.87^{\circ}C$. $q=1350\times5.82\times2.87$ $q = 1350\times16.7034$ $q = 22549.59\ J$

Step3: Convert joules to kilojoules

$1\ kJ = 1000\ J$, so $q=\frac{22549.59}{1000}=22.54959\ kJ\approx22.5\ kJ$

Answer:

22.5 kJ