a sample of substance x that has a mass of 326.0 g releases 4325.8 cal when it freezes at its freezing…

a sample of substance x that has a mass of 326.0 g releases 4325.8 cal when it freezes at its freezing point. if substance x has a molar mass of 58.45 g/mol, what is the molar heat of fusion for substance x? use $q = ndelta h$.\n13.31 cal/mol\n74.00 cal/mol\n775.6 cal/mol\n19054.7 cal/mol

a sample of substance x that has a mass of 326.0 g releases 4325.8 cal when it freezes at its freezing point. if substance x has a molar mass of 58.45 g/mol, what is the molar heat of fusion for substance x? use $q = ndelta h$.\n13.31 cal/mol\n74.00 cal/mol\n775.6 cal/mol\n19054.7 cal/mol

Answer

Explanation:

Step1: Calcular la cantidad de moles

Primero, usamos la masa y la masa molar para calcular el número de moles ($n$) de la sustancia X. La fórmula es $n=\frac{m}{M}$, donde $m = 326.0\ g$ y $M=58.45\ g/mol$. $n=\frac{326.0\ g}{58.45\ g/mol}\approx 5.58\ mol$

Step2: Calcular el calor molar de fusión

Sabemos que $q = n\Delta H$. Queremos encontrar $\Delta H$. Re - arreglamos la fórmula para $\Delta H=\frac{q}{n}$. Dado que $q = 4325.8\ cal$ y $n\approx5.58\ mol$. $\Delta H=\frac{4325.8\ cal}{5.58\ mol}\approx 775.6\ cal/mol$

Answer:

775.6 cal/mol