a scuba tank containing air holds 204 atm of gas. if air is 20.9% oxygen, what is the partial pressure of…

Explanation:

Step1: Identify the formula

The partial - pressure formula is $P_{i}=x_{i}P_{total}$, where $P_{i}$ is the partial pressure of component $i$, $x_{i}$ is the mole fraction of component $i$, and $P_{total}$ is the total pressure.

Step2: Convert the percentage to mole - fraction

The percentage of oxygen in air is 20.9%. To convert this to a mole - fraction, we divide by 100. So, $x_{O_{2}}=\frac{20.9}{100}=0.209$.

Step3: Calculate the partial pressure of oxygen

We know that $P_{total} = 204$ atm and $x_{O_{2}}=0.209$. Using the formula $P_{O_{2}}=x_{O_{2}}P_{total}$, we have $P_{O_{2}}=0.209\times204$ atm. $P_{O_{2}} = 0.209\times204=42.636$ atm.

Answer:

42.636 atm