section b: you may draw arrows to help you if you want but it is not required. write the names of the…
section b: you may draw arrows to help you if you want but it is not required. write the names of the elements in the order they appear in the formula from left to right. if the element appears more than once, only write it once, then add its atoms together.\n5) 3na₂so₄\n# of molecules\n# of elements\nname of element\n# of atoms\ntotal # of atoms\nthe #3 is a \n(coefficient or subscript)\n6) 2znso₄\n# of molecules\n# of elements\nname of element\n# of atoms\ntotal # of atoms\nthe #4 is a \n(coefficient or subscript)\n7) k₂co₃\n# of molecules\n# of elements\nname of element\n# of atoms\ntotal # of atoms\nthe #3 is a \n(coefficient or subscript)\n8) ba₃(po₄)₂\n# of molecules\n# of elements\nname of element\n# of atoms\ntotal # of atoms\nthe #3 is a \n(coefficient or subscript)\n9) na₂cro₄\n# of molecules\n# of elements\nname of element\n# of atoms\ntotal # of atoms\nthe #4 is a \n(coefficient or subscript)\n10) 4al₂(co₃)₃\n# of molecules\n# of elements\nname of element\n# of atoms\ntotal # of atoms\nthe assumed 1 is a \n(coefficient or subscript)
Answer
Explanation:
Step1: Analyze 3Na₂SO₄
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of molecules: 3 (the coefficient in front of the formula).
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of elements: 3 (sodium - Na, sulfur - S, oxygen - O).
- Names of elements: Sodium, Sulfur, Oxygen.
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of atoms: Na: 2×3 = 6, S: 1×3 = 3, O: 4×3 = 12. Total # of atoms: 6 + 3+12 = 21. The 3 is a coefficient.
Step2: Analyze 2ZnSO₄
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of molecules: 2.
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of elements: 3 (zinc - Zn, sulfur - S, oxygen - O).
- Names of elements: Zinc, Sulfur, Oxygen.
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of atoms: Zn: 1×2 = 2, S: 1×2 = 2, O: 4×2 = 8. Total # of atoms: 2 + 2+8 = 12. The 2 is a coefficient.
Step3: Analyze K₂CO₃
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of molecules: 1 (assumed when no coefficient is written).
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of elements: 3 (potassium - K, carbon - C, oxygen - O).
- Names of elements: Potassium, Carbon, Oxygen.
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of atoms: K: 2, C: 1, O: 3. Total # of atoms: 2 + 1+3 = 6. The 3 is a sub - script.
Step4: Analyze Ba₃(PO₄)₂
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of molecules: 1.
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of elements: 3 (barium - Ba, phosphorus - P, oxygen - O).
- Names of elements: Barium, Phosphorus, Oxygen.
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of atoms: Ba: 3, P: 1×2 = 2, O: 4×2 = 8. Total # of atoms: 3+2 + 8 = 13. The 3 is a sub - script.
Step5: Analyze Na₂CrO₄
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of molecules: 1.
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of elements: 3 (sodium - Na, chromium - Cr, oxygen - O).
- Names of elements: Sodium, Chromium, Oxygen.
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of atoms: Na: 2, Cr: 1, O: 4. Total # of atoms: 2 + 1+4 = 7. The 4 is a sub - script.
Step6: Analyze 4Al₂(CO₃)₃
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of molecules: 4.
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of elements: 3 (aluminum - Al, carbon - C, oxygen - O).
- Names of elements: Aluminum, Carbon, Oxygen.
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of atoms: Al: 2×4 = 8, C: 1×3×4 = 12, O: 3×3×4 = 36. Total # of atoms: 8+12 + 36 = 56. The 1 (assumed in CO₃) is a sub - script.
Answer:
| Chemical Formula | # of Molecules | # of Elements | Names of Elements | # of Atoms | Total # of Atoms | Coefficient/Sub - script |
|---|---|---|---|---|---|---|
| 3Na₂SO₄ | 3 | 3 | Sodium, Sulfur, Oxygen | Na: 6, S: 3, O: 12 | 21 | 3 is a coefficient |
| 2ZnSO₄ | 2 | 3 | Zinc, Sulfur, Oxygen | Zn: 2, S: 2, O: 8 | 12 | 2 is a coefficient |
| K₂CO₃ | 1 | 3 | Potassium, Carbon, Oxygen | K: 2, C: 1, O: 3 | 6 | 3 is a sub - script |
| Ba₃(PO₄)₂ | 1 | 3 | Barium, Phosphorus, Oxygen | Ba: 3, P: 2, O: 8 | 13 | 3 is a sub - script |
| Na₂CrO₄ | 1 | 3 | Sodium, Chromium, Oxygen | Na: 2, Cr: 1, O: 4 | 7 | 4 is a sub - script |
| 4Al₂(CO₃)₃ | 4 | 3 | Aluminum, Carbon, Oxygen | Al: 8, C: 12, O: 36 | 56 | 1 (in CO₃) is a sub - script |