7 select the balanced chemical equations (select all that apply): a 2 ch4 + 6 o2 → 2 co2 + 4 h2o b c3h6 + 5…

7 select the balanced chemical equations (select all that apply): a 2 ch4 + 6 o2 → 2 co2 + 4 h2o b c3h6 + 5 o2 → 3 co2 + 3 h2o c 2 cabr2 + na2co3 → 2 caco3 + 4 nabr d 4 ch4 + 5 o2 → 4 co2 + 6 h2o e c2h4 + o2 → 2 co2 + h2o

7 select the balanced chemical equations (select all that apply): a 2 ch4 + 6 o2 → 2 co2 + 4 h2o b c3h6 + 5 o2 → 3 co2 + 3 h2o c 2 cabr2 + na2co3 → 2 caco3 + 4 nabr d 4 ch4 + 5 o2 → 4 co2 + 6 h2o e c2h4 + o2 → 2 co2 + h2o

Answer

Explanation:

Step1: Check equation A

For carbon: In $2CH_4 + 6O_2\rightarrow2CO_2 + 4H_2O$, left - hand side has $2$ carbon atoms and right - hand side has $2$ carbon atoms. For hydrogen: left - hand side has $2\times4 = 8$ hydrogen atoms and right - hand side has $4\times2=8$ hydrogen atoms. For oxygen: left - hand side has $6\times2 = 12$ oxygen atoms and right - hand side has $(2\times2)+(4\times1)=8$ oxygen atoms. So equation A is unbalanced.

Step2: Check equation B

For carbon: In $C_3H_6+5O_2\rightarrow3CO_2 + 3H_2O$, left - hand side has $3$ carbon atoms and right - hand side has $3$ carbon atoms. For hydrogen: left - hand side has $6$ hydrogen atoms and right - hand side has $3\times2 = 6$ hydrogen atoms. For oxygen: left - hand side has $5\times2=10$ oxygen atoms and right - hand side has $(3\times2)+(3\times1)=9$ oxygen atoms. So equation B is unbalanced.

Step3: Check equation C

For calcium: In $2CaBr_2+Na_2CO_3\rightarrow2CaCO_3 + 4NaBr$, left - hand side has $2$ calcium atoms and right - hand side has $2$ calcium atoms. For bromine: left - hand side has $2\times2 = 4$ bromine atoms and right - hand side has $4$ bromine atoms. For sodium: left - hand side has $2$ sodium atoms and right - hand side has $4$ sodium atoms. For carbon: left - hand side has $1$ carbon atom and right - hand side has $2$ carbon atoms. For oxygen: left - hand side has $3$ oxygen atoms and right - hand side has $2\times3 = 6$ oxygen atoms. So equation C is unbalanced.

Step4: Check equation D

For carbon: In $4CH_4+5O_2\rightarrow4CO_2 + 6H_2O$, left - hand side has $4$ carbon atoms and right - hand side has $4$ carbon atoms. For hydrogen: left - hand side has $4\times4 = 16$ hydrogen atoms and right - hand side has $6\times2=12$ hydrogen atoms. For oxygen: left - hand side has $5\times2 = 10$ oxygen atoms and right - hand side has $(4\times2)+(6\times1)=14$ oxygen atoms. So equation D is unbalanced.

Step5: Check equation E

For carbon: In $C_2H_4+O_2\rightarrow2CO_2 + H_2O$, left - hand side has $2$ carbon atoms and right - hand side has $2$ carbon atoms. For hydrogen: left - hand side has $4$ hydrogen atoms and right - hand side has $2$ hydrogen atoms. For oxygen: left - hand side has $2$ oxygen atoms and right - hand side has $(2\times2)+1 = 5$ oxygen atoms. So equation E is unbalanced.

Answer:

None of the above