9 select the balanced chemical equations (select all that apply): a c₂h₂ + o₂ → 2 co₂ + h₂o b 2 c₃h₈ + 7 o₂…

Explanation:

Step1: Check option A

For $C_2H_2 + O_2\rightarrow2CO_2 + H_2O$, on the left - hand side, there are 2 C atoms, 2 H atoms and 2 O atoms. On the right - hand side, there are 2 C atoms, 2 H atoms and 5 O atoms. This equation is not balanced.

Step2: Check option B

For $2C_3H_8+7O_2\rightarrow6CO_2 + 8H_2O$, on the left - hand side, there are 6 C atoms ($2\times3$), 16 H atoms ($2\times8$) and 14 O atoms ($7\times2$). On the right - hand side, there are 6 C atoms ($6\times1$), 16 H atoms ($8\times2$) and 20 O atoms ($6\times2 + 8\times1$). This equation is not balanced.

Step3: Check option C

For $C_4H_{10}+5O_2\rightarrow4CO_2+6H_2O$, on the left - hand side, there are 4 C atoms, 10 H atoms and 10 O atoms. On the right - hand side, there are 4 C atoms, 12 H atoms and 14 O atoms. This equation is not balanced.

Step4: Check option D

For $2C_2H_4 + 3O_2\rightarrow4CO_2+4H_2O$, on the left - hand side, there are 4 C atoms ($2\times2$), 8 H atoms ($2\times4$) and 6 O atoms ($3\times2$). On the right - hand side, there are 4 C atoms ($4\times1$), 8 H atoms ($4\times2$) and 12 O atoms ($4\times2+4\times1$). This equation is not balanced.

Step5: Check option E

For $C_3H_8+5O_2\rightarrow3CO_2 + 6H_2O$, on the left - hand side, there are 3 C atoms, 8 H atoms and 10 O atoms. On the right - hand side, there are 3 C atoms ($3\times1$), 12 H atoms ($6\times2$) and 12 O atoms ($3\times2+6\times1$). This equation is not balanced.

Answer:

None of the above