select the correct answer. given: 2libr + ba → babr2 + 2li in this chemical reaction, 325 grams of barium…

Explanation:

Step1: Calculate moles of barium

The molar - mass of barium (Ba) is approximately 137.33 g/mol. Using the formula $n=\frac{m}{M}$, where $n$ is the number of moles, $m$ is the mass, and $M$ is the molar - mass. Given $m = 325$ g and $M=137.33$ g/mol, we have $n_{Ba}=\frac{325}{137.33}\approx2.37$ mol.

Step2: Determine mole ratio

From the balanced chemical equation $2LiBr + Ba\rightarrow BaBr_2+2Li$, the mole ratio of $Ba$ to $Li$ is $1:2$. That is, for every 1 mole of $Ba$ that reacts, 2 moles of $Li$ are produced.

Step3: Calculate moles of lithium

If $n_{Ba} = 2.37$ mol, then $n_{Li}=2\times n_{Ba}$. So $n_{Li}=2\times2.37 = 4.74$ mol (the small difference from 4.73 mol is due to rounding in the molar - mass value).

Answer:

C. 4.73 mol