select the correct answer. how many atoms of oxygen are contained in 160 grams of n₂o₃? a. 1.27×10²⁴ b…

Explanation:

Step1: Calculate molar mass of $N_2O_3$

The molar mass of $N$ is approximately $14.01\ g/mol$ and of $O$ is approximately $16.00\ g/mol$. For $N_2O_3$, $M = 2\times14.01+3\times16.00= 28.02 + 48.00=76.02\ g/mol$.

Step2: Calculate number of moles of $N_2O_3$

$n=\frac{m}{M}$, where $m = 160\ g$ and $M = 76.02\ g/mol$. So $n=\frac{160}{76.02}\approx2.105\ mol$.

Step3: Determine number of moles of oxygen

In one - mole of $N_2O_3$, there are 3 moles of oxygen. So in $2.105\ mol$ of $N_2O_3$, the number of moles of oxygen is $n_O=3\times2.105 = 6.315\ mol$.

Step4: Calculate number of oxygen atoms

Using Avogadro's number $N_A = 6.022\times10^{23}\ atoms/mol$, the number of oxygen atoms $N=n_O\times N_A=6.315\times6.022\times10^{23}\approx 3.80\times10^{24}$ atoms.

Answer:

C. $3.80\times 10^{24}$