select all the correct answers. a compound has the percent composition 47.40% pd, 28.50% o, 21.40% c, and…

select all the correct answers. a compound has the percent composition 47.40% pd, 28.50% o, 21.40% c, and 2.69% h. based on this information, which molecular formulas could represent the compound? pd2c8h12o8 pdo4c2h9 pd(o2c2h3)3 pd(o2c2ch3)2 pdo2c2h3

select all the correct answers. a compound has the percent composition 47.40% pd, 28.50% o, 21.40% c, and 2.69% h. based on this information, which molecular formulas could represent the compound? pd2c8h12o8 pdo4c2h9 pd(o2c2h3)3 pd(o2c2ch3)2 pdo2c2h3

Answer

Answer:

To solve this, we need to calculate the percent - composition of each given formula and compare with the given percentages.

  1. First, find the molar masses of elements:
    • Molar mass of Pd (palladium) (M_{Pd}=106.42\ g/mol)
    • Molar mass of O (oxygen) (M_O = 16.00\ g/mol)
    • Molar mass of C (carbon) (M_C=12.01\ g/mol)
    • Molar mass of H (hydrogen) (M_H = 1.01\ g/mol)
  2. For (Pd_2C_8H_{12}O_8):
    • Molar mass of the compound (M = 2\times106.42+8\times12.01 + 12\times1.01+8\times16.00)
      • (M = 212.84+96.08+12.12 + 128.00=449.04\ g/mol)
      • Percent of Pd: (\frac{2\times106.42}{449.04}\times100%=\frac{212.84}{449.04}\times100%\approx47.40%)
      • Percent of O: (\frac{8\times16.00}{449.04}\times100%=\frac{128.00}{449.04}\times100%\approx28.50%)
      • Percent of C: (\frac{8\times12.01}{449.04}\times100%=\frac{96.08}{449.04}\times100%\approx21.40%)
      • Percent of H: (\frac{12\times1.01}{449.04}\times100%=\frac{12.12}{449.04}\times100%\approx2.69%)
  3. For (PdO_4C_2H_9):
    • Molar mass of the compound (M = 106.42+4\times16.00+2\times12.01+9\times1.01)
      • (M = 106.42 + 64.00+24.02+9.09 = 203.53\ g/mol)
      • Percent of Pd: (\frac{106.42}{203.53}\times100%\approx52.38%) (not correct)
  4. For (Pd(O_2C_2H_3)_3):
    • First, the molar - mass of (O_2C_2H_3) is (2\times16.00+2\times12.01 + 3\times1.01=32.00+24.02+3.03 = 59.05\ g/mol)
    • Molar mass of (Pd(O_2C_2H_3)_3) is (106.42+3\times59.05=106.42 + 177.15=283.57\ g/mol)
      • Percent of Pd: (\frac{106.42}{283.57}\times100%\approx37.52%) (not correct)
  5. For (Pd(O_2CCH_3)_2):
    • Molar - mass of (O_2CCH_3) is (2\times16.00+2\times12.01+3\times1.01=32.00 + 24.02+3.03=59.05\ g/mol)
    • Molar mass of (Pd(O_2CCH_3)_2) is (106.42+2\times59.05=106.42+118.10 = 224.52\ g/mol)
      • Percent of Pd: (\frac{106.42}{224.52}\times100%\approx47.40%)
      • Percent of O: (\frac{2\times2\times16.00}{224.52}\times100%=\frac{64.00}{224.52}\times100%\approx28.50%)
      • Percent of C: (\frac{2\times2\times12.01}{224.52}\times100%=\frac{48.04}{224.52}\times100%\approx21.40%)
      • Percent of H: (\frac{2\times3\times1.01}{224.52}\times100%=\frac{6.06}{224.52}\times100%\approx2.69%)
  6. For (PdO_2C_2H_3):
    • Molar mass of the compound (M = 106.42+2\times16.00+2\times12.01+3\times1.01)
      • (M = 106.42+32.00+24.02+3.03 = 165.47\ g/mol)
      • Percent of Pd: (\frac{106.42}{165.47}\times100%\approx64.31%) (not correct)

The correct molecular formulas are (Pd_2C_8H_{12}O_8) and (Pd(O_2CCH_3)_2).

Answer:

Pd_2C_8H_{12}O_8, Pd(O_2CCH_3)_2

Explanation:

Step1: Determine molar masses of elements

(M_{Pd}=106.42\ g/mol), (M_O = 16.00\ g/mol), (M_C=12.01\ g/mol), (M_H = 1.01\ g/mol)

Step2: Calculate molar mass and percent - composition of (Pd_2C_8H_{12}O_8)

Find molar mass, then percents.

Step3: Calculate molar mass and percent - composition of (PdO_4C_2H_9)

Find molar mass, then percents (not a match).

Step4: Calculate molar mass and percent - composition of (Pd(O_2C_2H_3)_3)

Find molar mass, then percents (not a match).

Step5: Calculate molar mass and percent - composition of (Pd(O_2CCH_3)_2)

Find molar mass, then percents (a match).

Step6: Calculate molar mass and percent - composition of (PdO_2C_2H_3)

Find molar mass, then percents (not a match).