select one correct answer for each box. not all answers will be used. a. 1 b. 2 c. 3 d. 4 e. 6 f. 8 g. 18…

select one correct answer for each box. not all answers will be used. a. 1 b. 2 c. 3 d. 4 e. 6 f. 8 g. 18 2na2so4 element number of atoms sodium box 1 sulfur box 2 oxygen box 3 3co(no3)2 element number of atoms cobalt box 4 nitrogen box 5 oxygen box 6

select one correct answer for each box. not all answers will be used. a. 1 b. 2 c. 3 d. 4 e. 6 f. 8 g. 18 2na2so4 element number of atoms sodium box 1 sulfur box 2 oxygen box 3 3co(no3)2 element number of atoms cobalt box 4 nitrogen box 5 oxygen box 6

Answer

Explanation:

Step1: Calculate sodium atoms in $2Na_2SO_4$

The sub - script of Na is 2 and there is a coefficient of 2 in front of the formula. So the number of Na atoms is $2\times2 = 4$.

Step2: Calculate sulfur atoms in $2Na_2SO_4$

The sub - script of S is 1 and the coefficient is 2. So the number of S atoms is $1\times2=2$.

Step3: Calculate oxygen atoms in $2Na_2SO_4$

The sub - script of O is 4 and the coefficient is 2. So the number of O atoms is $4\times2 = 8$.

Step4: Calculate cobalt atoms in $3Co(NO_3)_2$

The sub - script of Co is 1 and the coefficient is 3. So the number of Co atoms is $1\times3 = 3$.

Step5: Calculate nitrogen atoms in $3Co(NO_3)_2$

The sub - script of N is 1 inside the nitrate ion, there are 2 nitrate ions and a coefficient of 3. So the number of N atoms is $1\times2\times3=6$.

Step6: Calculate oxygen atoms in $3Co(NO_3)_2$

The sub - script of O is 3 inside the nitrate ion, there are 2 nitrate ions and a coefficient of 3. So the number of O atoms is $3\times2\times3 = 18$.

Answer:

Box 1: D. 4 Box 2: B. 2 Box 3: F. 8 Box 4: C. 3 Box 5: E. 6 Box 6: G. 18