the sodium - 22 nuclide radioactively decays by positron emission. write a balanced nuclear chemical…

Explanation:

Step1: Identify the parent nuclide

Sodium - 22 has an atomic number of 11 and mass number of 22, written as $_{11}^{22}Na$.

Step2: Recall positron emission

In positron emission, a proton in the nucleus is converted into a neutron, a positron ($_{+1}^{0}e$) and a neutrino ($\nu$). The atomic number decreases by 1 and the mass number remains the same.

Step3: Determine the daughter nuclide

The daughter nuclide will have an atomic number of 10 (11 - 1) and mass number of 22. This is neon - 22, written as $_{10}^{22}Ne$.

Step4: Write the nuclear equation

The balanced nuclear chemical equation is ${11}^{22}Na\rightarrow{10}^{22}Ne + _{+1}^{0}e+\nu$.

Answer:

${11}^{22}Na\rightarrow{10}^{22}Ne + _{+1}^{0}e+\nu$