solid lead(ii) sulfide reacts with aqueous hydrobromic acid (hbr) to form solid lead(ii) bromide and…

solid lead(ii) sulfide reacts with aqueous hydrobromic acid (hbr) to form solid lead(ii) bromide and dihydrogen sulfide gas. express your answer as a chemical equation. identify all of the phases in your answer. a chemical reaction does not occur for this question. submit request answer part b gaseous carbon monoxide reacts with hydrogen gas to form gaseous methane (ch₄) and oxygen gas. express your answer as a chemical equation. identify all of the phases in your answer.

solid lead(ii) sulfide reacts with aqueous hydrobromic acid (hbr) to form solid lead(ii) bromide and dihydrogen sulfide gas. express your answer as a chemical equation. identify all of the phases in your answer. a chemical reaction does not occur for this question. submit request answer part b gaseous carbon monoxide reacts with hydrogen gas to form gaseous methane (ch₄) and oxygen gas. express your answer as a chemical equation. identify all of the phases in your answer.

Answer

Explanation:

Step1: Write reactants and products for first reaction

Solid lead(II) sulfide ($PbS(s)$), aqueous hydrobromic acid ($HBr(aq)$) are reactants. Solid lead(II) bromide ($PbBr_2(s)$) and dihydrogen sulfide gas ($H_2S(g)$) are products.

Step2: Balance the first reaction

$PbS(s)+2HBr(aq)\rightarrow PbBr_2(s)+H_2S(g)$

Step3: Write reactants and products for second reaction

Gaseous carbon - monoxide ($CO(g)$) and hydrogen gas ($H_2(g)$) are reactants. Gaseous methane ($CH_4(g)$) and oxygen gas ($O_2(g)$) are products.

Step4: Balance the second reaction

$2CO(g) + 4H_2(g)\rightarrow 2CH_4(g)+O_2(g)$

Answer:

$PbS(s)+2HBr(aq)\rightarrow PbBr_2(s)+H_2S(g)$ $2CO(g) + 4H_2(g)\rightarrow 2CH_4(g)+O_2(g)$