a solution of hcl has h⁺ = 0.01 m. what is the ph of this solution? use ph = -logh₃o⁺.\n-2\n-1\n1\n2

Explanation:

Step1: Identify the formula

The formula for pH is $pH = -\log[H^+]$.

Step2: Substitute the given value

Given $[H^+]=0.01\ M = 10^{- 2}\ M$. Then $pH=-\log(10^{-2})$.

Step3: Calculate the logarithm

According to the logarithm property $\log(a^b)=b\log(a)$, so $-\log(10^{-2})=-(-2)\log(10)$. Since $\log(10) = 1$, then $-(-2)\times1 = 2$.

Answer:

D. 2