a solution of hcl has h⁺ = 0.01 m. what is the ph of this solution? use ph = -logh₃o⁺.\no -2\no -1\no 1\no 2

Explanation:

Step1: Identify the formula

The formula for pH is $pH = -\log[H_3O^+]$, and here $[H^+]=[H_3O^+]=0.01\ M$.

Step2: Substitute the value

Substitute $[H_3O^+]=0.01 = 10^{- 2}$ into the formula: $pH=-\log(10^{-2})$.

Step3: Calculate the logarithm

According to the logarithm property $\log(a^b)=b\log(a)$, so $-\log(10^{-2})=-(-2)\log(10)$. Since $\log(10) = 1$, then $-(-2)\times1 = 2$.

Answer:

D. 2