a solution of hcl has h+ = 0.01 m. what is the ph of this solution? use ph=-logh3o+. -2 -1 1 2

Answer:

D. 2

Explanation:

Step1: Identify the formula

$pH = -\log[H^+]$

Step2: Substitute the given value

Given $[H^+]=0.01\ M = 1\times10^{- 2}\ M$. Then $pH=-\log(1\times 10^{-2})$.

Step3: Calculate the logarithm

We know that $\log(1\times 10^{-2})=-2$ (since $\log(a\times10^{n})=n$ when $a = 1$ in base - 10 logarithm). So $pH=-(-2)=2$.