a solution of hcl has h+ = 0.01 m. what is the ph of this solution? use ph = -logh3o+. -2 -1 1 2
a solution of hcl has h+ = 0.01 m. what is the ph of this solution? use ph = -logh3o+. -2 -1 1 2
Answer
Answer:
D. 2
Explanation:
Step1: Identify the formula
$\text{pH}=-\log[\text{H}_3\text{O}^+]$
Step2: Substitute the value
Given $[\text{H}^+]=[\text{H}_3\text{O}^+]= 0.01\ M = 1\times10^{-2}\ M$. Then $\text{pH}=-\log(1\times10^{-2})$.
Step3: Calculate the logarithm
Using the property of logarithms $\log(a\times10^{n})=n + \log(a)$, for $a = 1$ and $n=-2$, $\log(1\times10^{-2})=-2+\log(1)$. Since $\log(1) = 0$, $\log(1\times10^{-2})=-2$. So $\text{pH}=-(-2)=2$.