in the space station, liquid ammonia is used to transfer heat. if 100 g of liquid ammonia evaporates, then…

in the space station, liquid ammonia is used to transfer heat. if 100 g of liquid ammonia evaporates, then how much heat was removed? (δhᵥ = 5.65 kj/mol) 17.7 kj 33.2 kj 65.0 kj 565 kj

in the space station, liquid ammonia is used to transfer heat. if 100 g of liquid ammonia evaporates, then how much heat was removed? (δhᵥ = 5.65 kj/mol) 17.7 kj 33.2 kj 65.0 kj 565 kj

Answer

Explanation:

Step1: Calculate moles of ammonia

The molar - mass of ammonia ($NH_3$) is $M=(14 + 3\times1)\text{ g/mol}=17\text{ g/mol}$. The number of moles $n$ of $100\text{ g}$ of ammonia is $n=\frac{m}{M}=\frac{100\text{ g}}{17\text{ g/mol}}\approx5.88\text{ mol}$.

Step2: Calculate heat removed

The heat of vaporization $\Delta H_v = 5.65\text{ kJ/mol}$. The heat removed $q$ when the ammonia evaporates is given by $q = n\times\Delta H_v$. Substituting $n = 5.88\text{ mol}$ and $\Delta H_v=5.65\text{ kJ/mol}$, we get $q=5.88\text{ mol}\times5.65\text{ kJ/mol}\approx33.2\text{ kJ}$.

Answer:

33.2 kJ