a stock solution is made by dissolving 66.05 g of (nh4)2so4 in enough water to make 250 ml of solution. a…

a stock solution is made by dissolving 66.05 g of (nh4)2so4 in enough water to make 250 ml of solution. a 10.0 ml sample of this solution is then diluted to 50.0 ml. given that the molar mass of (nh4)2so4 is 132.1 g/mol, what is the concentration of the new solution? use mivi = mfvf and molarity = moles of solute / liters of solution. 0.400 m 1.60 m 5.00 m 10.0 m

a stock solution is made by dissolving 66.05 g of (nh4)2so4 in enough water to make 250 ml of solution. a 10.0 ml sample of this solution is then diluted to 50.0 ml. given that the molar mass of (nh4)2so4 is 132.1 g/mol, what is the concentration of the new solution? use mivi = mfvf and molarity = moles of solute / liters of solution. 0.400 m 1.60 m 5.00 m 10.0 m

Answer

Answer:

A. 0.400 M

Explanation:

Step1: Calculate moles of solute in stock solution

$n=\frac{m}{M}=\frac{66.05\ g}{132.1\ g/mol}=0.5\ mol$

Step2: Calculate molarity of stock solution

$M_i=\frac{n}{V}=\frac{0.5\ mol}{0.250\ L}=2\ M$

Step3: Use dilution formula

$M_iV_i = M_fV_f$, where $M_i = 2\ M$, $V_i=10.0\ mL = 0.0100\ L$, $V_f = 50.0\ mL=0.0500\ L$ $M_f=\frac{M_iV_i}{V_f}=\frac{2\ M\times0.0100\ L}{0.0500\ L}=0.400\ M$