at stp, what volume is required to hold 3.25 moles of an ideal gas?
at stp, what volume is required to hold 3.25 moles of an ideal gas?
Answer
Explanation:
Step1: Recall molar - volume at STP
At STP (Standard Temperature and Pressure), 1 mole of an ideal gas occupies 22.4 L.
Step2: Calculate the volume
We use the formula $V = n\times V_m$, where $n$ is the number of moles and $V_m$ is the molar - volume. Given $n = 3.25$ moles and $V_m=22.4$ L/mol. $V=3.25\ mol\times22.4\ L/mol$ $V = 72.8$ L
Answer:
72.8 L