at stp, what volume is required to hold 6.0 moles of an ideal gas?

at stp, what volume is required to hold 6.0 moles of an ideal gas?

at stp, what volume is required to hold 6.0 moles of an ideal gas?

Answer

Explanation:

Step1: Recall the molar - volume at STP

At STP (Standard Temperature and Pressure: 0°C or 273 K and 1 atm), 1 mole of an ideal gas occupies 22.4 L.

Step2: Calculate the volume for 6.0 moles

We use the proportion $V = n\times V_m$, where $n$ is the number of moles and $V_m$ is the molar - volume. Given $n = 6.0$ moles and $V_m=22.4$ L/mol. $V=6.0\ mol\times22.4\ L/mol$ $V = 134.4$ L

Answer:

134.4 L