9. the strongest oxidizing agent in the equations given above is\na. ce³⁺(aq)\nb. ce⁴⁺(aq)\nc. cd²⁺(aq)\nd…
9. the strongest oxidizing agent in the equations given above is\na. ce³⁺(aq)\nb. ce⁴⁺(aq)\nc. cd²⁺(aq)\nd. in³⁺(aq)\n\nequations of redox reactions\ni. 2ce⁴⁺(aq) + pd(s) → 2ce³⁺(aq) + pd²⁺(aq)\nii. pd²⁺(aq) + 2in³⁺(aq) → pd(s) + 2in³⁺(aq)\niii. cd²⁺(aq) + pd(s) → no reaction\niv. in³⁺(aq) + cd(s) → no reaction\nuse the following information to answer the next question.
Answer
Explanation:
Step1: Recall redox - reaction concept
In a redox reaction, a stronger oxidizing agent will oxidize a reducing agent. An oxidizing agent is reduced (gains electrons) in the reaction.
Step2: Analyze each reaction
In reaction I: (2Ce^{4 +}(aq)+Pd(s)\to2Ce^{3+}(aq)+Pd^{2+}(aq)), (Ce^{4+}) is reduced to (Ce^{3+}), so (Ce^{4+}) is an oxidizing agent. In reaction II: (Pd^{2+}(aq)+2In^{3+}(aq)\to Pd(s)+2In^{2+}(aq)), (Pd^{2+}) is reduced to (Pd), so (Pd^{2+}) is an oxidizing agent. In reaction III: (Cd^{2+}(aq)+Pd(s)\to) no reaction, (Cd^{2+}) cannot oxidize (Pd). In reaction IV: (In^{3+}(aq)+Cd(s)\to) no reaction, (In^{3+}) cannot oxidize (Cd).
Step3: Compare oxidizing - agent strength
Since (Ce^{4+}) can oxidize (Pd) (reaction I) and (Pd^{2+}) can oxidize (In^{3+}) (reaction II), and (Cd^{2+}) and (In^{3+}) show no - reaction with other species in the given reactions, the strongest oxidizing agent is (Ce^{4+}(aq)).
Answer:
B. (Ce^{4+}(aq))