a student balances the following redox reaction using half - reactions. al+mn^{2+}→al^{3+}+mn how many…
a student balances the following redox reaction using half - reactions. al+mn^{2+}→al^{3+}+mn how many electrons will be lost in all? 1 2 5 6
Answer
Explanation:
Step1: Write oxidation half - reaction
$Al\rightarrow Al^{3 +}+3e^{-}$
Step2: Determine total electrons lost
Since there are 2 Al atoms in the balanced overall reaction (to balance charges and atoms), total electrons lost is $2\times3 = 6$. The balanced overall reaction is $2Al + 3Mn^{2+}\rightarrow2Al^{3+}+3Mn$.
Answer:
6