a student balances the following redox reaction using half - reactions. al+mn2+→al3++mn how many electrons…
a student balances the following redox reaction using half - reactions. al+mn2+→al3++mn how many electrons will be lost in all? 1 2 5 6
Answer
Explanation:
Step1: Write oxidation half - reaction
Al $\rightarrow$ Al$^{3+}$ + 3e$^-$
Step2: Determine number of electrons lost per Al atom
Each Al atom loses 3 electrons.
Step3: Consider stoichiometry
In the balanced overall reaction, the coefficient of Al is 2 (after balancing the redox reaction: 2Al + 3Mn$^{2+}$ $\rightarrow$ 2Al$^{3+}$ + 3Mn). So total electrons lost = 2×3 = 6.
Answer:
6