a student prepares 150.0 ml of 1.40 m hcl using 35.0 ml of a stock solution. what is the concentration of…

a student prepares 150.0 ml of 1.40 m hcl using 35.0 ml of a stock solution. what is the concentration of the stock solution? use $m_iv_i = m_fv_f$. 0.327 m 4.29 m 6.00 m 7.35 m

a student prepares 150.0 ml of 1.40 m hcl using 35.0 ml of a stock solution. what is the concentration of the stock solution? use $m_iv_i = m_fv_f$. 0.327 m 4.29 m 6.00 m 7.35 m

Answer

Explanation:

Step1: Identify given values

$M_f = 1.40\ M$, $V_f=150.0\ mL$, $V_i = 35.0\ mL$

Step2: Rearrange the dilution formula

$M_i=\frac{M_fV_f}{V_i}$

Step3: Substitute values

$M_i=\frac{1.40\ M\times150.0\ mL}{35.0\ mL}$ $M_i=\frac{210}{35.0}\ M$ $M_i = 6.00\ M$

Answer:

C. 6.00 M