a student requires 2.00 l of 0.100 m nh4no3 from a 1.75 m nh4no3 stock solution. what is the correct way to…

a student requires 2.00 l of 0.100 m nh4no3 from a 1.75 m nh4no3 stock solution. what is the correct way to get the solution? use $m_iv_i = m_fv_f$. measure 114 ml of the 1.75 m solution, and dilute it to 1.00 l. measure 114 ml of the 1.75 m solution, and dilute it to 2.00 l. measure 8.75 ml of the 1.75 m solution, and dilute it to 2.00 l. measure 8.75 ml of the 0.100 m solution, and dilute it to 2.00 l.

a student requires 2.00 l of 0.100 m nh4no3 from a 1.75 m nh4no3 stock solution. what is the correct way to get the solution? use $m_iv_i = m_fv_f$. measure 114 ml of the 1.75 m solution, and dilute it to 1.00 l. measure 114 ml of the 1.75 m solution, and dilute it to 2.00 l. measure 8.75 ml of the 1.75 m solution, and dilute it to 2.00 l. measure 8.75 ml of the 0.100 m solution, and dilute it to 2.00 l.

Answer

Explanation:

Step1: Identify given values

$M_i = 1.75\ M$, $M_f=0.100\ M$, $V_f = 2.00\ L$

Step2: Rearrange the dilution formula $M_iV_i = M_fV_f$ for $V_i$

$V_i=\frac{M_fV_f}{M_i}$

Step3: Substitute values into the formula

$V_i=\frac{0.100\ M\times2.00\ L}{1.75\ M}=\frac{0.200}{1.75}\ L\approx0.114\ L = 114\ mL$ We want to make a final volume of $V_f = 2.00\ L$. So we measure 114 mL of the 1.75 M solution and dilute it to 2.00 L.

Answer:

Measure 114 mL of the 1.75 M solution, and dilute it to 2.00 L.