a student requires 2.00 l of 0.100 m nh4no3 from a 1.75 m nh4no3 stock solution. what is the correct way to…

a student requires 2.00 l of 0.100 m nh4no3 from a 1.75 m nh4no3 stock solution. what is the correct way to get the solution? use mivi = mfvf. measure 114 ml of the 1.75 m solution, and dilute it to 1.00 l. measure 114 ml of the 1.75 m solution, and dilute it to 2.00 l. measure 8.75 ml of the 1.75 m solution, and dilute it to 2.00 l. measure 8.75 ml of the 0.100 m solution, and dilute it to 2.00 l.

a student requires 2.00 l of 0.100 m nh4no3 from a 1.75 m nh4no3 stock solution. what is the correct way to get the solution? use mivi = mfvf. measure 114 ml of the 1.75 m solution, and dilute it to 1.00 l. measure 114 ml of the 1.75 m solution, and dilute it to 2.00 l. measure 8.75 ml of the 1.75 m solution, and dilute it to 2.00 l. measure 8.75 ml of the 0.100 m solution, and dilute it to 2.00 l.

Answer

Explanation:

Step1: Identify given values

$M_i = 1.75\ M$, $M_f=0.100\ M$, $V_f = 2.00\ L$

Step2: Rearrange dilution - formula

From $M_iV_i = M_fV_f$, we get $V_i=\frac{M_fV_f}{M_i}$

Step3: Substitute values

$V_i=\frac{0.100\ M\times2.00\ L}{1.75\ M}=\frac{0.200}{1.75}\ L$

Step4: Convert to mL

$V_i=\frac{0.200}{1.75}\ L\times1000\ mL/L\approx114\ mL$ The final volume should be $2.00\ L$. So, measure $114\ mL$ of the $1.75\ M$ solution and dilute it to $2.00\ L$.

Answer:

Measure 114 mL of the 1.75 M solution, and dilute it to 2.00 L.