a student takes a measured volume of 3.00 m hcl to prepare a 50.0 ml sample of 1.80 m hcl. what volume of…

a student takes a measured volume of 3.00 m hcl to prepare a 50.0 ml sample of 1.80 m hcl. what volume of 3.00 m hcl did the student use to make the sample? use $m_iv_i = m_fv_f$.\n3.70 ml\n16.7 ml\n30.0 ml\n83.3 ml

a student takes a measured volume of 3.00 m hcl to prepare a 50.0 ml sample of 1.80 m hcl. what volume of 3.00 m hcl did the student use to make the sample? use $m_iv_i = m_fv_f$.\n3.70 ml\n16.7 ml\n30.0 ml\n83.3 ml

Answer

Explanation:

Step1: Identify given values

$M_i = 3.00\ M$, $V_f=50.0\ mL$, $M_f = 1.80\ M$

Step2: Rearrange the dilution formula

From $M_iV_i = M_fV_f$, we can solve for $V_i$ as $V_i=\frac{M_fV_f}{M_i}$

Step3: Substitute values

$V_i=\frac{1.80\ M\times50.0\ mL}{3.00\ M}$ $V_i = 30.0\ mL$

Answer:

30.0 mL