be sure to use proper significant figures. the molecular weight of nacl is 58.44 grams/mole. with a 0.50 m…

Answer:

0.29 g

Explanation:

Step1: Convert volume to liters

$V = 10.0\ mL=10.0\times10^{- 3}\ L = 0.0100\ L$

Step2: Calculate moles of NaCl

$n = M\times V$, where $M = 0.50\ mol/L$ and $V = 0.0100\ L$. So $n=0.50\ mol/L\times0.0100\ L = 0.0050\ mol$

Step3: Calculate mass of NaCl

$m=n\times MW$, where $MW = 58.44\ g/mol$ and $n = 0.0050\ mol$. So $m = 0.0050\ mol\times58.44\ g/mol=0.2922\ g$. Rounding to two - significant figures gives $m = 0.29\ g$