the symbol for a radioactive nuclide is $_{84}^{210}po$. which statement is correct?\nthe atomic number of…
the symbol for a radioactive nuclide is $_{84}^{210}po$. which statement is correct?\nthe atomic number of the radioactive nuclide is 210.\nthe mass number of the radioactive nuclide is 294.\nthe number of neutrons present in the nucleus of each atom is 126.\nthe number of protons present in the nucleus of each atom is 210.
Answer
Explanation:
Step1: Recall nuclide notation
In the notation ${Z}^{A}X$, $A$ is the mass - number and $Z$ is the atomic number. For ${84}^{210}Po$, $A = 210$ and $Z=84$.
Step2: Calculate number of neutrons
The number of neutrons $N$ is given by $N=A - Z$. So, $N = 210-84=126$.
Step3: Analyze each option
- Option 1: The atomic number $Z = 84$, not 210.
- Option 2: The mass number $A = 210$, not 294.
- Option 3: Since $N=A - Z=210 - 84 = 126$, this option is correct.
- Option 4: The number of protons is equal to the atomic number, so the number of protons is 84, not 210.
Answer:
The number of neutrons present in the nucleus of each atom is 126.