does taking 1 ml of solution y (pure bleach) out of the first beaker change the solutions concentration…

does taking 1 ml of solution y (pure bleach) out of the first beaker change the solutions concentration? what would the concentration of the second beaker be? if beaker #2 is a 1% solution of y, and beaker #3 is 1/100th of that in the final solution, what percentage solution would beaker #3 be?

does taking 1 ml of solution y (pure bleach) out of the first beaker change the solutions concentration? what would the concentration of the second beaker be? if beaker #2 is a 1% solution of y, and beaker #3 is 1/100th of that in the final solution, what percentage solution would beaker #3 be?

Answer

Explanation:

Step1: Determine if concentration changes in Beaker #1

For a homogeneous solution like pure bleach in Beaker #1, taking out a small - volume sample does not change the concentration of the remaining solution. The concentration is an intensive property. So the answer to the first question is no.

Step2: Calculate concentration of Beaker #2

We use the formula for dilution $C_1V_1 = C_2V_2$. In Beaker #1, $C_1 = 100%$ (pure bleach), $V_1=1\ mL$, and $V_2=(99 + 1)\ mL = 100\ mL$. Substituting into the formula: $100%\times1\ mL=C_2\times100\ mL$. Solving for $C_2$, we get $C_2=\frac{100%\times1\ mL}{100\ mL}=1%$.

Step3: Calculate concentration of Beaker #3

If Beaker #2 has a concentration of $1%$ and Beaker #3 is $\frac{1}{100}$th of that, then the concentration of Beaker #3 is $1%\times\frac{1}{100}=0.01%$.

Answer:

No 1% 0.01%