during trial 2, what allowed you to determine that aluminum was the limiting reactant? check all that apply…

during trial 2, what allowed you to determine that aluminum was the limiting reactant? check all that apply. all of the copper dissolved. all of the aluminum dissolved. the solution turned clear. the number of grams of copper(ii) chloride used in the reaction was greater than the number of grams of aluminum. the molar ratio of copper(ii) chloride to aluminum was greater than 3:2, the equations molar ratio. done

during trial 2, what allowed you to determine that aluminum was the limiting reactant? check all that apply. all of the copper dissolved. all of the aluminum dissolved. the solution turned clear. the number of grams of copper(ii) chloride used in the reaction was greater than the number of grams of aluminum. the molar ratio of copper(ii) chloride to aluminum was greater than 3:2, the equations molar ratio. done

Answer

Answer:

  • B. All of the aluminum dissolved.
  • E. The molar ratio of copper(II) chloride to aluminum was greater than 3:2, the equation's molar ratio.

Brief Explanations:

When all of the aluminum dissolves, it indicates it is the limiting reactant as it is completely consumed first. A molar - ratio of copper(II) chloride to aluminum greater than the stoichiometric 3:2 means there is more copper(II) chloride relative to aluminum, suggesting aluminum will run out first and thus is the limiting reactant.