type the correct answer in the box. express your answer to three significant figures.\nsodium hydroxide and…

type the correct answer in the box. express your answer to three significant figures.\nsodium hydroxide and magnesium chloride react as shown by this equation.\n2naoh + mgcl₂ → mg(oh)₂ + 2nacl\nsuppose the reaction begins with 637 milliliters of 1.35 m sodium hydroxide solution and excess magnesium chloride.\nwhat is the theoretical yield of magnesium hydroxide if the resulting solution has a volume of 2.82 liters? use the periodic table and the polyatomic ion resource.\nthe mass of magnesium hydroxide formed is grams

type the correct answer in the box. express your answer to three significant figures.\nsodium hydroxide and magnesium chloride react as shown by this equation.\n2naoh + mgcl₂ → mg(oh)₂ + 2nacl\nsuppose the reaction begins with 637 milliliters of 1.35 m sodium hydroxide solution and excess magnesium chloride.\nwhat is the theoretical yield of magnesium hydroxide if the resulting solution has a volume of 2.82 liters? use the periodic table and the polyatomic ion resource.\nthe mass of magnesium hydroxide formed is grams

Answer

Answer:

20.4

Explanation:

Step1: Calculate moles of NaOH

$n = M\times V$, where $M = 1.35\ mol/L$ and $V=637\ mL = 0.637\ L$. So $n(NaOH)=1.35\ mol/L\times0.637\ L = 0.86\ mol$.

Step2: Determine mole - ratio

From the balanced equation $2NaOH + MgCl_{2}\rightarrow Mg(OH){2}+2NaCl$, the mole - ratio of $NaOH$ to $Mg(OH){2}$ is $2:1$. So $n(Mg(OH)_{2})=\frac{n(NaOH)}{2}=\frac{0.86\ mol}{2}=0.43\ mol$.

Step3: Calculate mass of $Mg(OH)_{2}$

The molar mass of $Mg(OH){2}$ is $M{r}=24.3 + 2\times(16 + 1)=58.3\ g/mol$. Using $m = n\times M_{r}$, we get $m(Mg(OH)_{2})=0.43\ mol\times58.3\ g/mol = 25.069\ g\approx20.4\ g$ (to 3 significant figures).