type the correct answer in the box. a lab technician needs to create 570.0 milliliters of a 2.00 m solution…

type the correct answer in the box. a lab technician needs to create 570.0 milliliters of a 2.00 m solution of magnesium chloride (mgcl2). to make this solution, how many grams of magnesium chloride does the technician need? refer to the periodic table for help. express your answer to three significant figures. the required mass is grams.

type the correct answer in the box. a lab technician needs to create 570.0 milliliters of a 2.00 m solution of magnesium chloride (mgcl2). to make this solution, how many grams of magnesium chloride does the technician need? refer to the periodic table for help. express your answer to three significant figures. the required mass is grams.

Answer

Explanation:

Step1: Calculate the number of moles

Use the formula $n = M\times V$, where $M$ is molarity and $V$ is volume in liters. First, convert volume to liters: $V=570.0\ mL = 0.570\ L$, $M = 2.00\ mol/L$. Then $n = 2.00\ mol/L\times0.570\ L=1.14\ mol$.

Step2: Calculate the molar - mass of $MgCl_2$

From the periodic table, the molar mass of $Mg$ is $24.31\ g/mol$ and the molar mass of $Cl$ is $35.45\ g/mol$. For $MgCl_2$, $M_{MgCl_2}=24.31\ g/mol + 2\times35.45\ g/mol=24.31\ g/mol + 70.90\ g/mol = 95.21\ g/mol$.

Step3: Calculate the mass of $MgCl_2$

Use the formula $m=n\times M$. Substitute $n = 1.14\ mol$ and $M = 95.21\ g/mol$ into the formula: $m=1.14\ mol\times95.21\ g/mol = 108.5394\ g$.

Step4: Round to three significant figures

Rounding $108.5394\ g$ to three significant figures gives $109\ g$.

Answer:

109