type the correct answer in the box. during a water treatment program, 127 grams of calcium nitrate…

type the correct answer in the box. during a water treatment program, 127 grams of calcium nitrate, ca(no₃)₂, is dissolved in water. the final volume of the solution is 2,300 milliliters. what is the molarity of the solution? refer to the periodic table to help you answer. express your answer to two significant figures. the molarity of the solution is m.

type the correct answer in the box. during a water treatment program, 127 grams of calcium nitrate, ca(no₃)₂, is dissolved in water. the final volume of the solution is 2,300 milliliters. what is the molarity of the solution? refer to the periodic table to help you answer. express your answer to two significant figures. the molarity of the solution is m.

Answer

Explanation:

Step1: Calculate molar mass of $Ca(NO_3)_2$

The molar mass of $Ca$ is $40.08\ g/mol$, $N$ is $14.01\ g/mol$, and $O$ is $16.00\ g/mol$. $M_{Ca(NO_3)_2}=40.08 + 2\times(14.01+3\times16.00)=40.08+2\times(14.01 + 48.00)=40.08+2\times62.01=40.08 + 124.02=164.1\ g/mol$

Step2: Calculate number of moles of $Ca(NO_3)_2$

$n=\frac{m}{M}$, where $m = 127\ g$ and $M = 164.1\ g/mol$. $n=\frac{127\ g}{164.1\ g/mol}\approx0.774\ mol$

Step3: Convert volume to liters

$V = 2300\ mL=2.300\ L$

Step4: Calculate molarity

$M=\frac{n}{V}$, where $n = 0.774\ mol$ and $V = 2.300\ L$. $M=\frac{0.774\ mol}{2.300\ L}\approx0.34\ M$

Answer:

$0.34$