an unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below. bf₃…

an unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below. bf₃ + li₂so₃ → b₂(so₃)₃ + lif what is the coefficient of lithium fluoride in the balanced chemical reaction? 1 3 4 6

an unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below. bf₃ + li₂so₃ → b₂(so₃)₃ + lif what is the coefficient of lithium fluoride in the balanced chemical reaction? 1 3 4 6

Answer

Explanation:

Step1: Balance boron atoms

There are 1 boron atom on the left - hand side and 2 boron atoms on the right - hand side. Multiply (BF_3) by 2: (2BF_3+Li_2SO_3\rightarrow B_2(SO_3)_3 + LiF).

Step2: Balance sulfur and oxygen atoms

There is 1 (SO_3) group on the left - hand side and 3 (SO_3) groups on the right - hand side. Multiply (Li_2SO_3) by 3: (2BF_3 + 3Li_2SO_3\rightarrow B_2(SO_3)_3+LiF).

Step3: Balance lithium and fluorine atoms

After multiplying (BF_3) by 2 and (Li_2SO_3) by 3, there are 6 lithium atoms and 6 fluorine atoms on the left - hand side. So, multiply (LiF) by 6 to balance the equation: (2BF_3+3Li_2SO_3\rightarrow B_2(SO_3)_3 + 6LiF).

Answer:

D. 6