use the data in the table to answer the following questions. how many grams of compound were…

use the data in the table to answer the following questions. how many grams of compound were formed?\naluminum and liquid bromine reaction\n| |before reaction|after reaction|\n|--|--|--|\n|aluminum|10.3 g|0.0 g|\n|liquid bromine|100.0 g|8.5 g|\n|compound|0.0 g|\n100.0 g\n101.8 g\n10.3 g\n91.5 g

use the data in the table to answer the following questions. how many grams of compound were formed?\naluminum and liquid bromine reaction\n| |before reaction|after reaction|\n|--|--|--|\n|aluminum|10.3 g|0.0 g|\n|liquid bromine|100.0 g|8.5 g|\n|compound|0.0 g|\n100.0 g\n101.8 g\n10.3 g\n91.5 g

Answer

Explanation:

Step1: Calculate used liquid bromine mass

Mass of used liquid bromine = Initial mass - Remaining mass = $100.0 - 8.5=91.5$ g

Step2: Apply law of conservation of mass

According to the law of conservation of mass, mass of compound formed = Mass of aluminum used+Mass of used liquid bromine. Mass of aluminum used is 10.3 g and mass of used liquid bromine is 91.5 g. So mass of compound formed = $10.3 + 91.5=101.8$ g

Answer:

101.8 g