use the following balanced equation to answer the questions: 2al + 3s → al₂s₃ there are 2 moles of al…

use the following balanced equation to answer the questions: 2al + 3s → al₂s₃ there are 2 moles of al present. the molar mass of aluminum is 26.98 g/mol. what mass of aluminum is present?

use the following balanced equation to answer the questions: 2al + 3s → al₂s₃ there are 2 moles of al present. the molar mass of aluminum is 26.98 g/mol. what mass of aluminum is present?

Answer

Answer:

53.96 g

Explanation:

Step1: Recall mass - mole formula

$m = n\times M$ where $m$ is mass, $n$ is number of moles, and $M$ is molar mass.

Step2: Identify given values

$n = 2\ mol$ (moles of Al), $M=26.98\ g/mol$ (molar mass of Al)

Step3: Calculate mass

$m=2\ mol\times26.98\ g/mol = 53.96\ g$