use the following balanced equation to answer the questions: na₂o + h₂o → 2naoh there is 1 mole of h₂o…

use the following balanced equation to answer the questions: na₂o + h₂o → 2naoh there is 1 mole of h₂o present. the molar mass of water is 18.02 g/mol. what mass of water is present?
Answer
Answer:
18.02 g
Explanation:
Step1: Recall mass - mole relationship
$m = n\times M$ where $m$ is mass, $n$ is number of moles and $M$ is molar mass.
Step2: Identify given values
$n = 1$ mol (moles of $H_2O$), $M=18.02$ g/mol (molar mass of $H_2O$)
Step3: Calculate mass of water
$m=1\ mol\times18.02\ g/mol = 18.02$ g