use the periodic to fill in the numbers in the electron configurations shown below. b: 1s² 2s^a2p^b a = b =
use the periodic to fill in the numbers in the electron configurations shown below. b: 1s² 2s^a2p^b a = b =
Answer
Explanation:
Step1: Identify element B
Boron (B) has an atomic number of 5, which means it has 5 electrons.
Step2: Analyze electron - shell filling rules
Electrons fill the 1s orbital first. The 1s orbital can hold a maximum of 2 electrons, so it is filled as $1s^{2}$. Then, electrons fill the 2s orbital. The 2s orbital can also hold a maximum of 2 electrons, so $A = 2$.
Step3: Calculate remaining electrons
After filling the 1s and 2s orbitals, we have used 2 + 2=4 electrons. Since boron has 5 electrons, the remaining 1 electron goes into the 2p orbital. So $B = 1$.
Answer:
A = 2 B = 1