use the periodic table to determine the electron configuration for aluminum (al) and arsenic (as) in noble…

use the periodic table to determine the electron configuration for aluminum (al) and arsenic (as) in noble - gas notation.\nal:\nar3s²3p¹\nhe2s²2p⁶3s²3p¹\nne3s²3p¹\nne3s²3p²\ndone

use the periodic table to determine the electron configuration for aluminum (al) and arsenic (as) in noble - gas notation.\nal:\nar3s²3p¹\nhe2s²2p⁶3s²3p¹\nne3s²3p¹\nne3s²3p²\ndone

Answer

Explanation:

Step1: Recall aluminum's atomic number

Aluminum (Al) has an atomic number of 13.

Step2: Identify the nearest noble - gas

The nearest noble - gas with a lower atomic number than Al is neon (Ne), which has an atomic number of 10.

Step3: Determine the remaining electrons

After accounting for the 10 electrons of Ne, there are 13 - 10=3 remaining electrons.

Step4: Write the electron configuration

These 3 electrons fill the 3s and 3p orbitals as $3s^{2}3p^{1}$. So the noble - gas notation for Al is $[Ne]3s^{2}3p^{1}$.

Answer:

[Ne]3s²3p¹