what volume of a 0.100 m agno₃ solution is required to completely react with the cacl₂ in 3.00 l of a 0.100…

Explanation:

Step1: Calculate moles of CaCl₂

Use the formula $n = M\times V$, where $M$ is molarity and $V$ is volume. Given $M_{CaCl_2}=0.100\ M$ and $V_{CaCl_2}=3.00\ L$. So $n_{CaCl_2}=0.100\ mol/L\times3.00\ L = 0.300\ mol$.

Step2: Determine moles of AgNO₃

From the balanced - chemical equation $2AgNO_3 + CaCl_2\rightarrow2AgCl + Ca(NO_3)2$, the mole ratio of $AgNO_3$ to $CaCl_2$ is $2:1$. So $n{AgNO_3}=2\times n_{CaCl_2}=2\times0.300\ mol = 0.600\ mol$.

Step3: Calculate volume of AgNO₃ solution

Use the formula $V=\frac{n}{M}$. Given $n_{AgNO_3}=0.600\ mol$ and $M_{AgNO_3}=0.100\ M$. So $V_{AgNO_3}=\frac{0.600\ mol}{0.100\ mol/L}=6.00\ L$.

Answer:

$6.00$