what volume of a 3.95 m potassium chloride solution would be needed to make 325 ml of a 2.76 m solution by…

Explanation:

Step1: Identify dilution formula

The dilution formula is $M_1V_1 = M_2V_2$, where $M_1$ and $V_1$ are the molarity and volume of the initial solution, and $M_2$ and $V_2$ are the molarity and volume of the final solution.

Step2: Assign values

$M_1 = 3.95\ M$, $M_2=2.76\ M$, $V_2 = 325\ mL$. We need to find $V_1$.

Step3: Rearrange formula for $V_1$

$V_1=\frac{M_2V_2}{M_1}$

Step4: Substitute values and calculate

$V_1=\frac{2.76\ M\times325\ mL}{3.95\ M}$ $V_1=\frac{897\ M\cdot mL}{3.95\ M}=227\ mL$

Answer:

227 mL