what volume (in liters) does 3.91 moles of nitrogen gas at 4,066 torr and 323 k occupy? g : n = 3.91 mol p =…

what volume (in liters) does 3.91 moles of nitrogen gas at 4,066 torr and 323 k occupy? g : n = 3.91 mol p = 4,066 torr t = 323 k u : v = ? l e : pv = nrt *use r = 62.4 \\frac{l\\cdot torr}{mol\\cdot k}

what volume (in liters) does 3.91 moles of nitrogen gas at 4,066 torr and 323 k occupy? g : n = 3.91 mol p = 4,066 torr t = 323 k u : v = ? l e : pv = nrt *use r = 62.4 \\frac{l\\cdot torr}{mol\\cdot k}

Answer

Explanation:

Step1: Rearrange the ideal - gas law for volume.

Given $PV = nRT$, we can solve for $V$ as $V=\frac{nRT}{P}$.

Step2: Substitute the given values into the formula.

We have $n = 3.91\ mol$, $R=62.4\frac{L\cdot torr}{mol\cdot K}$, $T = 323\ K$, and $P = 4066\ torr$. $V=\frac{3.91\ mol\times62.4\frac{L\cdot torr}{mol\cdot K}\times323\ K}{4066\ torr}$

Step3: Calculate the volume.

First, calculate the numerator: $3.91\times62.4\times323 = 3.91\times20155.2=78806.832$. Then, divide by the denominator: $V=\frac{78806.832}{4066}\approx19.4\ L$.

Answer:

$19.4$