what volume will 2.0 moles of nitrogen occupy at 720 torr and 20.0°c? formula: $pv = nrt$ ($r = 62.396 lcdot…

what volume will 2.0 moles of nitrogen occupy at 720 torr and 20.0°c? formula: $pv = nrt$ ($r = 62.396 lcdot torr/molcdot k$) 3.5 l 6.6 l 48 l 51 l done

what volume will 2.0 moles of nitrogen occupy at 720 torr and 20.0°c? formula: $pv = nrt$ ($r = 62.396 lcdot torr/molcdot k$) 3.5 l 6.6 l 48 l 51 l done

Answer

Explanation:

Step1: Convert temperature to Kelvin

$T = 20.0 + 273.15=293.15\ K$

Step2: Rearrange the ideal - gas law for volume

$V=\frac{nRT}{P}$

Step3: Substitute the given values

$n = 2.0\ mol$, $R = 62.396\ L\cdot torr/mol\cdot K$, $T = 293.15\ K$, $P = 720\ torr$ $V=\frac{2.0\ mol\times62.396\ L\cdot torr/mol\cdot K\times293.15\ K}{720\ torr}$ $V=\frac{2.0\times62.396\times293.15}{720}\ L$ $V\approx 51\ L$

Answer:

D. 51 L