we wish to determine the moles of co₂ produced when 50.0 ml of 2.0 m hcl reacts with excess…

we wish to determine the moles of co₂ produced when 50.0 ml of 2.0 m hcl reacts with excess na₂co₃.\n2hcl(aq) + na₂co₃(aq) → 2nacl(aq) + h₂o(l) + co₂(g)\nhow many moles of hcl are present in 50.0 ml of 2.0 m hcl?

we wish to determine the moles of co₂ produced when 50.0 ml of 2.0 m hcl reacts with excess na₂co₃.\n2hcl(aq) + na₂co₃(aq) → 2nacl(aq) + h₂o(l) + co₂(g)\nhow many moles of hcl are present in 50.0 ml of 2.0 m hcl?

Answer

Explanation:

Step1: Recall molarity formula

$n = M\times V$ (where $n$ is moles, $M$ is molarity, $V$ is volume in L).

Step2: Convert volume to L

$V = 50.0\ mL=0.0500\ L$.

Step3: Calculate moles of HCl

$n = 2.0\ mol/L\times0.0500\ L = 0.1\ mol$.

Answer:

$0.1\ mol$