write the balanced dissociation equation for solid iron(iii) hydroxide in aqueous solution. if it does not…

write the balanced dissociation equation for solid iron(iii) hydroxide in aqueous solution. if it does not dissociate, simply write only nr. be sure to include the proper phases for all species within the reaction.

write the balanced dissociation equation for solid iron(iii) hydroxide in aqueous solution. if it does not dissociate, simply write only nr. be sure to include the proper phases for all species within the reaction.

Answer

Explanation:

Step1: Identify reactant and products

Iron(III) hydroxide ($Fe(OH)_3$) dissociates into iron(III) ion ($Fe^{3 + }$) and hydroxide ions ($OH^-$) in water. $Fe(OH)_3(s)\rightarrow Fe^{3 + }(aq)+3OH^-(aq)$

Step2: Balance the equation

The equation is already balanced as there is 1 iron atom, 3 oxygen atoms and 3 hydrogen atoms on both sides.

Answer:

$Fe(OH)_3(s)\rightleftharpoons Fe^{3 + }(aq)+3OH^-(aq)$