write the equilibrium constant expression for this reaction: ch₃cl(aq)+oh⁻(aq) → ch₃oh(aq)+cl⁻(aq)

Explanation:

Step1: Recall equilibrium - constant formula

For a general reaction $aA + bB\rightleftharpoons cC + dD$, the equilibrium - constant expression $K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}$, where $[ ]$ represents the molar concentration of the species and $a,b,c,d$ are the stoichiometric coefficients.

Step2: Identify species and coefficients in given reaction

In the reaction $\mathrm{CH_3Cl}(aq)+\mathrm{OH^-}(aq)\rightleftharpoons\mathrm{CH_3OH}(aq)+\mathrm{Cl^-}(aq)$, the stoichiometric coefficients of all species are 1.

Step3: Write the equilibrium - constant expression

$K_c=\frac{[\mathrm{CH_3OH}][\mathrm{Cl^-}]}{[\mathrm{CH_3Cl}][\mathrm{OH^-}]}$

Answer:

$K_c=\frac{[\mathrm{CH_3OH}][\mathrm{Cl^-}]}{[\mathrm{CH_3Cl}][\mathrm{OH^-}]}$