if you have 100 grams of $n_2$ and excess $o_2$, how many grams of no can be produced? $n_2 + o_2 -> 2no$…

Answer:

C. 214 grams NO

Explanation:

Step1: Calculate moles of N₂

The molar mass of N₂ is $M_{N_2}=2\times14\ g/mol = 28\ g/mol$. The number of moles of N₂, $n_{N_2}=\frac{m_{N_2}}{M_{N_2}}=\frac{100\ g}{28\ g/mol}\approx3.57\ mol$.

Step2: Use mole - ratio

From the balanced chemical equation $N_2 + O_2\rightarrow2NO$, the mole - ratio of $N_2$ to $NO$ is 1:2. So the number of moles of NO produced, $n_{NO}=2\times n_{N_2}=2\times3.57\ mol = 7.14\ mol$.

Step3: Calculate mass of NO

The molar mass of NO is $M_{NO}=14 + 16=30\ g/mol$. The mass of NO, $m_{NO}=n_{NO}\times M_{NO}=7.14\ mol\times30\ g/mol = 214.2\ g\approx214\ g$.