brandon is going to invest in an account paying an interest rate of 4.6% compounded annually. how much would…

brandon is going to invest in an account paying an interest rate of 4.6% compounded annually. how much would brandon need to invest, to the nearest ten dollars, for the value of the account to reach $69,000 in 8 years?

brandon is going to invest in an account paying an interest rate of 4.6% compounded annually. how much would brandon need to invest, to the nearest ten dollars, for the value of the account to reach $69,000 in 8 years?

Answer

Explanation:

Step1: Use compound - interest formula

The compound - interest formula is $A = P(1 + r)^t$, where $A=$69000$, $r = 0.046$, $t = 8$. We need to solve for $P$. Rearranging gives $P=\frac{A}{(1 + r)^t}$.

Step2: Substitute values

Substitute $A = 69000$, $r=0.046$, $t = 8$ into the formula: $P=\frac{69000}{(1 + 0.046)^8}$.

Step3: Calculate

First, calculate $(1+0.046)^8=(1.046)^8\approx1.4423$. Then $P=\frac{69000}{1.4423}\approx47839.0$. Rounding to the nearest ten dollars gives $P = 47840$.

Answer:

$47840$